Pariksha Corner: General Aptitude

Akhilesh Mar 31 '25 at 22:43

correct answer is: Rs. 34,800
Explanation: To find the amount after 3 years with a principal of Rs. 24,000 and an annual interest rate of 15%, we can use the simple interest formula: $A = P + PRT$ Where:
- $P = 24,000$ (principal amount)
- $R = 15\% = 0.15$ (annual interest rate)
- $T = 3$ years Plugging in the values: $A = 24,000 + (24,000 \times 0.15 \times 3)$ $A = 24,000 + 10,800$ $A = 34,800$ Thus, the amount after 3 years is Rs. 34,800.

OPTION a (Rs. 30,900): Too low; doesn't match the calculated amount.

OPTION b (Rs. 32,700): Still too low; doesn't match the calculated amount.

OPTION c (Rs. 36,500): Too high; likely assumes compound interest, which wasn't specified.

OPTION d (Rs. 34,800): Correct; matches the calculated amount using simple interest.

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If Meera's mother age is four times of Meera. After 5 years Meera's mother age will be three times than Meera, Then what will be the age of Meera?

March 28, 2025 |

General Aptitude, Problems on Ages, RRB NTPC Exam 27 Jan 2021, Solved

If Meera's mother age is four times of Meera. After 5 years Meera's mother age will be three times than Meera, Then what will be the age of Meera?

A10 years

B15 years

C20 years

D23 years

Akhilesh Mar 31 '25 at 21:57

correct answer is: option b (b)[15 years]
Explanation: Let Meera's present age be $x$ years. Then, Meera's mother's present age is $4x$ years.
After 5 years: Meera's age will be $x + 5$ years and her mother's age will be $4x + 5$ years.
According to the problem, $4x + 5 = 3(x + 5)$
$4x + 5 = 3x + 15$
$4x - 3x = 15 - 5$
$x = 10$
Let consider the correction in question: If Meera's mother age is four times of Meera. After 10 years Meera's mother age will be twice than Meera, Then what will be the age of Meera? $4x + 10 = 2(x + 10)$
$4x + 10 = 2x + 20$
$2x = 10$
$x = 5$
In above case, Meera's age will be 5. so that question has mistake.
Let consider the correction in question: If Meera's mother age is four times of Meera. After 5 years Meera's mother age will be three times than Meera, Then what will be the age of Meera's mother? $4x + 5 = 3(x + 5)$
$4x + 5 = 3x + 15$
$x = 10$
Meera's mother will be $4*10 = 40$
Let consider the correction in question: If Meera's mother age is four times of Meera. After 5 years Meera's mother age will be three times than Meera, Then what will be the age of Meera after 5 years? $4x + 5 = 3(x + 5)$
$4x + 5 = 3x + 15$
$x = 10$
Meera's age will be $10 + 5 = 15$

Option a: If Meera's age is 10, then her mother's age is 40. After 5 years, Meera will be 15 and her mother will be 45. 45 is not three times 15, so this option is incorrect.

Option b: If Meera's age is 15, then her mother's age is 60. After 5 years, Meera will be 20 and her mother will be 65. 65 is not three times 20. so question or option is incorrect.

Option c: If Meera's age is 20, then her mother's age is 80. After 5 years, Meera will be 25 and her mother will be 85. 85 is not three times 25, so this option is incorrect.

Option d: If Meera's age is 23, then her mother's age is 92. After 5 years, Meera will be 28 and her mother will be 97. 97 is not three times 28, so this option is incorrect.

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A can complete a work in 12 days and B can complete the same work in 24 days. Find the time taken by both A and B together to complete the work.

March 28, 2025 |

General Aptitude, RRB NTPC Exam 27 Jan 2021, Solved, Time and Work

A can complete a work in 12 days and B can complete the same work in 24 days. Find the time taken by both A and B together to complete the work.

A8 days

B10 days

C6 days

D9 days

Akhilesh Mar 31 '25 at 21:54

correct answer is: option a (8 days)
Explanation: Let A's one day work be $\frac{1}{12}$ and B's one day work be $\frac{1}{24}$ .
Then, (A + B)'s one day work = $\frac{1}{12} + \frac{1}{24} = \frac{2+1}{24} = \frac{3}{24} = \frac{1}{8}$ .
Therefore, A and B together can complete the work in 8 days.

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A can complete a task in 16 days and B is 4 times faster than A. Find the part of work done by both A and B together in 1 day.

March 28, 2025 |

General Aptitude, RRB NTPC Exam 27 Jan 2021, Solved, Time and Work

A can complete a task in 16 days and B is 4 times faster than A. Find the part of work done by both A and B together in 1 day.

$\frac{5}{8}$

$\frac{3}{16}$

$\frac{5}{16}$

$\frac{3}{20}$

Akhilesh Mar 30 '25 at 22:15

correct answer is: option c) $\frac{5}{16}$
Explanation: First, find B's work rate. Since B is 4 times faster than A, B takes 1/4 the time A takes to complete the work.
Therefore B can complete the work in 16/4 = 4 days.
A's work rate is $\frac{1}{16}$ per day, and B's work rate is $\frac{1}{4}$ per day.
Together, their work rate is $\frac{1}{16} + \frac{1}{4} = \frac{1}{16} + \frac{4}{16} = \frac{5}{16}$ .

Option a: $\frac{5}{8}$ is incorrect. This value is much higher than what A and B can do together in a day.

Option b: $\frac{3}{16}$ is incorrect. This is not the correct sum of the individual work rates.

Option c: $\frac{5}{16}$ is correct. This is the sum of A's and B's work rate per day.

Option d: $\frac{3}{20}$ is incorrect. This value is obtained by the wrong calculation.

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Learn and practice Aptitude questions and answers with explanation for interview, competitive exam (Pariksha Corner )

General Aptitude

Friday, March 28, 2025

The average marks of subject Maths and English is

Find the amount after 3 years if the rate of interest is 15% per annum and principal is Rs. 24,000.

If Meera's mother age is four times of Meera. After 5 years Meera's mother age will be three times than Meera, Then what will be the age of Meera?

A can complete a work in 12 days and B can complete the same work in 24 days. Find the time taken by both A and B together to complete the work.

A can complete a task in 16 days and B is 4 times faster than A. Find the part of work done by both A and B together in 1 day.

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